114281313127 has 2 divisors, whose sum is σ = 114281313128. Its totient is φ = 114281313126.

The previous prime is 114281313109. The next prime is 114281313161. The reversal of 114281313127 is 721313182411.

It is an a-pointer prime, because the next prime (114281313161) can be obtained adding 114281313127 to its sum of digits (34).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114281313127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114281313092 and 114281313101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114281313197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57140656563 + 57140656564.

It is an arithmetic number, because the mean of its divisors is an integer number (57140656564).

Almost surely, 2^114281313127 is an apocalyptic number.

114281313127 is a deficient number, since it is larger than the sum of its proper divisors (1).

114281313127 is an equidigital number, since it uses as much as digits as its factorization.

114281313127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8064, while the sum is 34.

Adding to 114281313127 its reverse (721313182411), we get a palindrome (835594495538).

The spelling of 114281313127 in words is "one hundred fourteen billion, two hundred eighty-one million, three hundred thirteen thousand, one hundred twenty-seven".