Base | Representation |
---|---|
bin | 11001111111010010001110… |
… | …001001001001100100001011 |
3 | 112222200222102022121120022212 |
4 | 121333102032021021210023 |
5 | 104440143002414204144 |
6 | 1043032415313535335 |
7 | 33034622621313143 |
oct | 3177221611114413 |
9 | 488628368546285 |
10 | 114300054444299 |
11 | 33468420a34949 |
12 | 109a0148b7454b |
13 | 4ba15ab27ba49 |
14 | 203221b715923 |
15 | d33317a3349e |
hex | 67f48e24990b |
114300054444299 has 2 divisors, whose sum is σ = 114300054444300. Its totient is φ = 114300054444298.
The previous prime is 114300054444227. The next prime is 114300054444371. The reversal of 114300054444299 is 992444450003411.
It is a balanced prime because it is at equal distance from previous prime (114300054444227) and next prime (114300054444371).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114300054444299 is a prime.
It is not a weakly prime, because it can be changed into another prime (114302054444299) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150027222149 + 57150027222150.
It is an arithmetic number, because the mean of its divisors is an integer number (57150027222150).
Almost surely, 2114300054444299 is an apocalyptic number.
114300054444299 is a deficient number, since it is larger than the sum of its proper divisors (1).
114300054444299 is an equidigital number, since it uses as much as digits as its factorization.
114300054444299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2488320, while the sum is 50.
The spelling of 114300054444299 in words is "one hundred fourteen trillion, three hundred billion, fifty-four million, four hundred forty-four thousand, two hundred ninety-nine".
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