Base | Representation |
---|---|
bin | 11001111111010010001110… |
… | …001001100100001000111001 |
3 | 112222200222102022211002122012 |
4 | 121333102032021210020321 |
5 | 104440143002431200040 |
6 | 1043032415320135305 |
7 | 33034622622245366 |
oct | 3177221611441071 |
9 | 488628368732565 |
10 | 114300054553145 |
11 | 33468420aa96aa |
12 | 109a0149007535 |
13 | 4ba15ab2b9456 |
14 | 203221b74346d |
15 | d33317a55865 |
hex | 67f48e264239 |
114300054553145 has 8 divisors (see below), whose sum is σ = 137160484528200. Its totient is φ = 91439764266240.
The previous prime is 114300054553109. The next prime is 114300054553169. The reversal of 114300054553145 is 541355450003411.
It can be written as a sum of positive squares in 4 ways, for example, as 1221756619561 + 113078297933584 = 1105331^2 + 10633828^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 114300054553145 - 232 = 114295759585849 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33113366 + ... + 36401855.
It is an arithmetic number, because the mean of its divisors is an integer number (17145060566025).
Almost surely, 2114300054553145 is an apocalyptic number.
It is an amenable number.
114300054553145 is a deficient number, since it is larger than the sum of its proper divisors (22860429975055).
114300054553145 is an equidigital number, since it uses as much as digits as its factorization.
114300054553145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69844075.
The product of its (nonzero) digits is 360000, while the sum is 41.
The spelling of 114300054553145 in words is "one hundred fourteen trillion, three hundred billion, fifty-four million, five hundred fifty-three thousand, one hundred forty-five".
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