Base | Representation |
---|---|
bin | 11001111111010010010010… |
… | …110010111101000111101011 |
3 | 112222200222121202111211101220 |
4 | 121333102102302331013223 |
5 | 104440143132410342420 |
6 | 1043032431143113123 |
7 | 33034624560011355 |
oct | 3177222262750753 |
9 | 488628552454356 |
10 | 114300132512235 |
11 | 334684610064aa |
12 | 109a016b1427a3 |
13 | 4ba15c14b38a7 |
14 | 2032227c380d5 |
15 | d3331e804840 |
hex | 67f492cbd1eb |
114300132512235 has 64 divisors (see below), whose sum is σ = 186563909145600. Its totient is φ = 59739826798080.
The previous prime is 114300132512191. The next prime is 114300132512287. The reversal of 114300132512235 is 532215231003411.
It is a happy number.
It is not a de Polignac number, because 114300132512235 - 213 = 114300132504043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114300132512196 and 114300132512205.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 390400372 + ... + 390693038.
It is an arithmetic number, because the mean of its divisors is an integer number (2915061080400).
Almost surely, 2114300132512235 is an apocalyptic number.
114300132512235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114300132512235 is a deficient number, since it is larger than the sum of its proper divisors (72263776633365).
114300132512235 is a wasteful number, since it uses less digits than its factorization.
114300132512235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 294308.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 114300132512235 its reverse (532215231003411), we get a palindrome (646515363515646).
The spelling of 114300132512235 in words is "one hundred fourteen trillion, three hundred billion, one hundred thirty-two million, five hundred twelve thousand, two hundred thirty-five".
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