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114300325541 is a prime number
BaseRepresentation
bin110101001110011010…
…1001000111010100101
3101221000210020011000102
41222130311020322211
53333041340404131
6124301524353445
711154316510463
oct1523465107245
9357023204012
10114300325541
1144524610366
121a19ab45885
13aa1740162c
145764393833
152e8e8e31cb
hex1a9cd48ea5

114300325541 has 2 divisors, whose sum is σ = 114300325542. Its totient is φ = 114300325540.

The previous prime is 114300325523. The next prime is 114300325543. The reversal of 114300325541 is 145523003411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71893160641 + 42407164900 = 268129^2 + 205930^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114300325541 is a prime.

Together with 114300325543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114300325543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57150162770 + 57150162771.

It is an arithmetic number, because the mean of its divisors is an integer number (57150162771).

Almost surely, 2114300325541 is an apocalyptic number.

It is an amenable number.

114300325541 is a deficient number, since it is larger than the sum of its proper divisors (1).

114300325541 is an equidigital number, since it uses as much as digits as its factorization.

114300325541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 114300325541 its reverse (145523003411), we get a palindrome (259823328952).

The spelling of 114300325541 in words is "one hundred fourteen billion, three hundred million, three hundred twenty-five thousand, five hundred forty-one".