Base | Representation |
---|---|
bin | 10101010010100100… |
… | …11100101010110001 |
3 | 1002111120210021002222 |
4 | 22221102130222301 |
5 | 141402102320423 |
6 | 5130111050425 |
7 | 553151263226 |
oct | 125122345261 |
9 | 32446707088 |
10 | 11430120113 |
11 | 4936006465 |
12 | 226bb10a15 |
13 | 11020837a9 |
14 | 7a607594d |
15 | 46d7023c8 |
hex | 2a949cab1 |
11430120113 has 2 divisors, whose sum is σ = 11430120114. Its totient is φ = 11430120112.
The previous prime is 11430120071. The next prime is 11430120127. The reversal of 11430120113 is 31102103411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9563275264 + 1866844849 = 97792^2 + 43207^2 .
It is a cyclic number.
It is not a de Polignac number, because 11430120113 - 26 = 11430120049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11430120091 and 11430120100.
It is not a weakly prime, because it can be changed into another prime (11430120133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715060056 + 5715060057.
It is an arithmetic number, because the mean of its divisors is an integer number (5715060057).
Almost surely, 211430120113 is an apocalyptic number.
It is an amenable number.
11430120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11430120113 is an equidigital number, since it uses as much as digits as its factorization.
11430120113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11430120113 its reverse (31102103411), we get a palindrome (42532223524).
The spelling of 11430120113 in words is "eleven billion, four hundred thirty million, one hundred twenty thousand, one hundred thirteen".
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