Base | Representation |
---|---|
bin | 10101010010100101… |
… | …00010010010000111 |
3 | 1002111120211102122202 |
4 | 22221102202102013 |
5 | 141402104034421 |
6 | 5130111345115 |
7 | 553151420252 |
oct | 125122422207 |
9 | 32446742582 |
10 | 11430143111 |
11 | 4936021772 |
12 | 226bb2219b |
13 | 11020910ba |
14 | 7a6080099 |
15 | 46d70910b |
hex | 2a94a2487 |
11430143111 has 2 divisors, whose sum is σ = 11430143112. Its totient is φ = 11430143110.
The previous prime is 11430143059. The next prime is 11430143113. The reversal of 11430143111 is 11134103411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11430143111 - 214 = 11430126727 is a prime.
Together with 11430143113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11430143113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715071555 + 5715071556.
It is an arithmetic number, because the mean of its divisors is an integer number (5715071556).
Almost surely, 211430143111 is an apocalyptic number.
11430143111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11430143111 is an equidigital number, since it uses as much as digits as its factorization.
11430143111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11430143111 its reverse (11134103411), we get a palindrome (22564246522).
The spelling of 11430143111 in words is "eleven billion, four hundred thirty million, one hundred forty-three thousand, one hundred eleven".
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