Base | Representation |
---|---|
bin | 10101010010100110… |
… | …01100000010001001 |
3 | 1002111121011010020110 |
4 | 22221103030002021 |
5 | 141402130022441 |
6 | 5130115144533 |
7 | 553153031652 |
oct | 125123140211 |
9 | 32447133213 |
10 | 11430314121 |
11 | 49361291a6 |
12 | 226bba5149 |
13 | 1102120ba5 |
14 | 7a60c6529 |
15 | 46d73eb16 |
hex | 2a94cc089 |
11430314121 has 4 divisors (see below), whose sum is σ = 15240418832. Its totient is φ = 7620209412.
The previous prime is 11430314111. The next prime is 11430314143. The reversal of 11430314121 is 12141303411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 11430314121 - 215 = 11430281353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11430314111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905052351 + ... + 1905052356.
It is an arithmetic number, because the mean of its divisors is an integer number (3810104708).
Almost surely, 211430314121 is an apocalyptic number.
It is an amenable number.
11430314121 is a deficient number, since it is larger than the sum of its proper divisors (3810104711).
11430314121 is an equidigital number, since it uses as much as digits as its factorization.
11430314121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3810104710.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 11430314121 its reverse (12141303411), we get a palindrome (23571617532).
The spelling of 11430314121 in words is "eleven billion, four hundred thirty million, three hundred fourteen thousand, one hundred twenty-one".
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