Base | Representation |
---|---|
bin | 11001111111011101010110… |
… | …010001110110100011101111 |
3 | 112222202010020222020112122111 |
4 | 121333131112101312203233 |
5 | 104440341440014303120 |
6 | 1043042113033424451 |
7 | 33035524655612665 |
oct | 3177352621664357 |
9 | 488663228215574 |
10 | 114312002103535 |
11 | 334724a2097095 |
12 | 109a252226b127 |
13 | 4ba27636188b2 |
14 | 2032a323cac35 |
15 | d337b68b575a |
hex | 67f7564768ef |
114312002103535 has 32 divisors (see below), whose sum is σ = 145772037450432. Its totient is φ = 85757015070720.
The previous prime is 114312002103527. The next prime is 114312002103547. The reversal of 114312002103535 is 535301200213411.
It is not a de Polignac number, because 114312002103535 - 23 = 114312002103527 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114312002103497 and 114312002103506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1475126140 + ... + 1475203630.
It is an arithmetic number, because the mean of its divisors is an integer number (4555376170326).
Almost surely, 2114312002103535 is an apocalyptic number.
114312002103535 is a deficient number, since it is larger than the sum of its proper divisors (31460035346897).
114312002103535 is a wasteful number, since it uses less digits than its factorization.
114312002103535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140443.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 114312002103535 its reverse (535301200213411), we get a palindrome (649613202316946).
The spelling of 114312002103535 in words is "one hundred fourteen trillion, three hundred twelve billion, two million, one hundred three thousand, five hundred thirty-five".
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