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114312210334253 is a prime number
BaseRepresentation
bin11001111111011101100010…
…101100001100001000101101
3112222202010210111001202111022
4121333131202230030020231
5104440342401321144003
61043042145432503525
733035533064550431
oct3177354254141055
9488663714052438
10114312210334253
1133472599690998
12109a257bb4aba5
134ba27977c5339
142032a51d129c1
15d337c9ce8738
hex67f762b0c22d

114312210334253 has 2 divisors, whose sum is σ = 114312210334254. Its totient is φ = 114312210334252.

The previous prime is 114312210334243. The next prime is 114312210334319. The reversal of 114312210334253 is 352433012213411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114271032996169 + 41177338084 = 10689763^2 + 202922^2 .

It is a cyclic number.

It is not a de Polignac number, because 114312210334253 - 228 = 114311941898797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114312210334213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57156105167126 + 57156105167127.

It is an arithmetic number, because the mean of its divisors is an integer number (57156105167127).

Almost surely, 2114312210334253 is an apocalyptic number.

It is an amenable number.

114312210334253 is a deficient number, since it is larger than the sum of its proper divisors (1).

114312210334253 is an equidigital number, since it uses as much as digits as its factorization.

114312210334253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 114312210334253 its reverse (352433012213411), we get a palindrome (466745222547664).

The spelling of 114312210334253 in words is "one hundred fourteen trillion, three hundred twelve billion, two hundred ten million, three hundred thirty-four thousand, two hundred fifty-three".