Base | Representation |
---|---|
bin | 11001111111011110110000… |
… | …110101111000110100110111 |
3 | 112222202021011212020212000011 |
4 | 121333132300311320310313 |
5 | 104440403043000440242 |
6 | 1043042523511401051 |
7 | 33035610425352454 |
oct | 3177366065706467 |
9 | 488667155225004 |
10 | 114313521499447 |
11 | 33473101814796 |
12 | 109a2887083187 |
13 | 4ba294633c32a |
14 | 2032b380dc82b |
15 | d33854e91d17 |
hex | 67f7b0d78d37 |
114313521499447 has 2 divisors, whose sum is σ = 114313521499448. Its totient is φ = 114313521499446.
The previous prime is 114313521499439. The next prime is 114313521499459. The reversal of 114313521499447 is 744994125313411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114313521499447 - 23 = 114313521499439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114313521499391 and 114313521499400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114313521499417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57156760749723 + 57156760749724.
It is an arithmetic number, because the mean of its divisors is an integer number (57156760749724).
Almost surely, 2114313521499447 is an apocalyptic number.
114313521499447 is a deficient number, since it is larger than the sum of its proper divisors (1).
114313521499447 is an equidigital number, since it uses as much as digits as its factorization.
114313521499447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13063680, while the sum is 58.
The spelling of 114313521499447 in words is "one hundred fourteen trillion, three hundred thirteen billion, five hundred twenty-one million, four hundred ninety-nine thousand, four hundred forty-seven".
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