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114320113142345 = 51117122267500687
BaseRepresentation
bin11001111111100100111001…
…101111000000101001001001
3112222202220012020121000011022
4121333210321233000221021
5104441010042431023340
61043045533541242225
733036232655402315
oct3177447157005111
9488686166530138
10114320113142345
1133475984605650
12109a4006703375
134ba3456b68b46
1420331a171ab45
15d33add9e63b5
hex67f939bc0a49

114320113142345 has 16 divisors (see below), whose sum is σ = 158458680891648. Its totient is φ = 78251200439040.

The previous prime is 114320113142327. The next prime is 114320113142351. The reversal of 114320113142345 is 543241311023411.

It is not a de Polignac number, because 114320113142345 - 214 = 114320113125961 is a prime.

It is a super-3 number, since 3×1143201131423453 (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61133749409 + ... + 61133751278.

It is an arithmetic number, because the mean of its divisors is an integer number (9903667555728).

Almost surely, 2114320113142345 is an apocalyptic number.

It is an amenable number.

114320113142345 is a deficient number, since it is larger than the sum of its proper divisors (44138567749303).

114320113142345 is a wasteful number, since it uses less digits than its factorization.

114320113142345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122267500720.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 114320113142345 its reverse (543241311023411), we get a palindrome (657561424165756).

The spelling of 114320113142345 in words is "one hundred fourteen trillion, three hundred twenty billion, one hundred thirteen million, one hundred forty-two thousand, three hundred forty-five".

Divisors: 1 5 11 17 55 85 187 935 122267500687 611337503435 1344942507557 2078547511679 6724712537785 10392737558395 22864022628469 114320113142345