Base | Representation |
---|---|
bin | 110101001111000010… |
… | …0100001011011000101 |
3 | 101221002020101101122021 |
4 | 1222132010201123011 |
5 | 3333112202312201 |
6 | 124303550403141 |
7 | 11154661421362 |
oct | 1523604413305 |
9 | 357066341567 |
10 | 114321135301 |
11 | 4453533400a |
12 | 1a1a5b004b1 |
13 | aa1b8094b9 |
14 | 576704d469 |
15 | 2e91653ea1 |
hex | 1a9e1216c5 |
114321135301 has 2 divisors, whose sum is σ = 114321135302. Its totient is φ = 114321135300.
The previous prime is 114321135287. The next prime is 114321135323. The reversal of 114321135301 is 103531123411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107436450625 + 6884684676 = 327775^2 + 82974^2 .
It is a cyclic number.
It is not a de Polignac number, because 114321135301 - 211 = 114321133253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114321135361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57160567650 + 57160567651.
It is an arithmetic number, because the mean of its divisors is an integer number (57160567651).
Almost surely, 2114321135301 is an apocalyptic number.
It is an amenable number.
114321135301 is a deficient number, since it is larger than the sum of its proper divisors (1).
114321135301 is an equidigital number, since it uses as much as digits as its factorization.
114321135301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 114321135301 its reverse (103531123411), we get a palindrome (217852258712).
The spelling of 114321135301 in words is "one hundred fourteen billion, three hundred twenty-one million, one hundred thirty-five thousand, three hundred one".
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