114331025551 has 4 divisors (see below), whose sum is σ = 114358962952. Its totient is φ = 114303088152.

The previous prime is 114331025489. The next prime is 114331025617. The reversal of 114331025551 is 155520133411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155520133411 = 49393 ⋅3148627.

It is a cyclic number.

It is not a de Polignac number, because 114331025551 - 2¹¹ = 114331023503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114331028551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13962561 + ... + 13970746.

It is an arithmetic number, because the mean of its divisors is an integer number (28589740738).

Almost surely, 2^114331025551 is an apocalyptic number.

114331025551 is a deficient number, since it is larger than the sum of its proper divisors (27937401).

114331025551 is an equidigital number, since it uses as much as digits as its factorization.

114331025551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27937400.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 114331025551 its reverse (155520133411), we get a palindrome (269851158962).

The spelling of 114331025551 in words is "one hundred fourteen billion, three hundred thirty-one million, twenty-five thousand, five hundred fifty-one".