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114331301141 is a prime number
BaseRepresentation
bin110101001111010101…
…1010011010100010101
3101221002221111212112212
41222132223103110111
53333122303114031
6124304552323205
711155144011401
oct1523653232425
9357087455485
10114331301141
1144540047832
121a1a93a3505
13aa209586a5
145768538101
152e924b112b
hex1a9ead3515

114331301141 has 2 divisors, whose sum is σ = 114331301142. Its totient is φ = 114331301140.

The previous prime is 114331301093. The next prime is 114331301173. The reversal of 114331301141 is 141103133411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111806640625 + 2524660516 = 334375^2 + 50246^2 .

It is a cyclic number.

It is not a de Polignac number, because 114331301141 - 210 = 114331300117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114331301341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57165650570 + 57165650571.

It is an arithmetic number, because the mean of its divisors is an integer number (57165650571).

Almost surely, 2114331301141 is an apocalyptic number.

It is an amenable number.

114331301141 is a deficient number, since it is larger than the sum of its proper divisors (1).

114331301141 is an equidigital number, since it uses as much as digits as its factorization.

114331301141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 114331301141 its reverse (141103133411), we get a palindrome (255434434552).

The spelling of 114331301141 in words is "one hundred fourteen billion, three hundred thirty-one million, three hundred one thousand, one hundred forty-one".