Search a number
-
+
11433140143 = 23349069271
BaseRepresentation
bin10101010010111011…
…11101111110101111
31002111210110200210221
422221131331332233
5141403340441033
65130255512211
7553216042045
oct125135757657
932453420727
1011433140143
114937789457
122270b28667
1311028a02a9
147a6620395
1546daec12d
hex2a977dfaf

11433140143 has 4 divisors (see below), whose sum is σ = 11482209648. Its totient is φ = 11384070640.

The previous prime is 11433140137. The next prime is 11433140167. The reversal of 11433140143 is 34104133411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34104133411 = 58395840749.

It is a cyclic number.

It is not a de Polignac number, because 11433140143 - 221 = 11431042991 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11433141143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24534403 + ... + 24534868.

It is an arithmetic number, because the mean of its divisors is an integer number (2870552412).

Almost surely, 211433140143 is an apocalyptic number.

11433140143 is a deficient number, since it is larger than the sum of its proper divisors (49069505).

11433140143 is an equidigital number, since it uses as much as digits as its factorization.

11433140143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49069504.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11433140143 its reverse (34104133411), we get a palindrome (45537273554).

The spelling of 11433140143 in words is "eleven billion, four hundred thirty-three million, one hundred forty thousand, one hundred forty-three".

Divisors: 1 233 49069271 11433140143