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114331432003142 = 2173362689176563
BaseRepresentation
bin11001111111101111011100…
…011001000010011001000110
3112222210222102002000201011212
4121333233130121002121012
5104441201233043100032
61043055045035531422
733040113316210424
oct3177573431023106
9488728362021155
10114331432003142
113347a76282a262
12109a62452b9b72
134ba453bb66003
142033956ab0114
15d3405256cbb2
hex67fbdc642646

114331432003142 has 8 divisors (see below), whose sum is σ = 181585215534456. Its totient is φ = 53803026824992.

The previous prime is 114331432003097. The next prime is 114331432003153. The reversal of 114331432003142 is 241300234133411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 114331432003099 and 114331432003108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1681344588248 + ... + 1681344588315.

It is an arithmetic number, because the mean of its divisors is an integer number (22698151941807).

Almost surely, 2114331432003142 is an apocalyptic number.

114331432003142 is a deficient number, since it is larger than the sum of its proper divisors (67253783531314).

114331432003142 is a wasteful number, since it uses less digits than its factorization.

114331432003142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3362689176582.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 114331432003142 its reverse (241300234133411), we get a palindrome (355631666136553).

The spelling of 114331432003142 in words is "one hundred fourteen trillion, three hundred thirty-one billion, four hundred thirty-two million, three thousand, one hundred forty-two".

Divisors: 1 2 17 34 3362689176563 6725378353126 57165716001571 114331432003142