Base | Representation |
---|---|
bin | 11001111111110001010100… |
… | …000101010100101100001100 |
3 | 112222211011121000121122202111 |
4 | 121333301110011110230030 |
5 | 104441214341131214012 |
6 | 1043100020212233404 |
7 | 33040214141600500 |
oct | 3177612405245414 |
9 | 488734530548674 |
10 | 114333440101132 |
11 | 334805a32a7a7a |
12 | 109a670590b864 |
13 | 4ba479bbb7285 |
14 | 2033aa7676300 |
15 | d3411d9ceba7 |
hex | 67fc54154b0c |
114333440101132 has 18 divisors (see below), whose sum is σ = 232750217349132. Its totient is φ = 49000045757544.
The previous prime is 114333440101121. The next prime is 114333440101187. The reversal of 114333440101132 is 231101044333411.
It is a junction number, because it is equal to n+sod(n) for n = 114333440101094 and 114333440101103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 291666938838 + ... + 291666939229.
Almost surely, 2114333440101132 is an apocalyptic number.
It is an amenable number.
114333440101132 is an abundant number, since it is smaller than the sum of its proper divisors (118416777248000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114333440101132 is a wasteful number, since it uses less digits than its factorization.
114333440101132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 583333878085 (or 583333878076 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 114333440101132 its reverse (231101044333411), we get a palindrome (345434484434543).
The spelling of 114333440101132 in words is "one hundred fourteen trillion, three hundred thirty-three billion, four hundred forty million, one hundred one thousand, one hundred thirty-two".
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