11433420133 has 2 divisors, whose sum is σ = 11433420134. Its totient is φ = 11433420132.

The previous prime is 11433420121. The next prime is 11433420139. The reversal of 11433420133 is 33102433411.

11433420133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7184596644 + 4248823489 = 84762^2 + 65183^2 .

It is a cyclic number.

It is not a de Polignac number, because 11433420133 - 2⁵ = 11433420101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11433420098 and 11433420107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11433420139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716710066 + 5716710067.

It is an arithmetic number, because the mean of its divisors is an integer number (5716710067).

Almost surely, 2^11433420133 is an apocalyptic number.

It is an amenable number.

11433420133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11433420133 is an equidigital number, since it uses as much as digits as its factorization.

11433420133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11433420133 its reverse (33102433411), we get a palindrome (44535853544).

The spelling of 11433420133 in words is "eleven billion, four hundred thirty-three million, four hundred twenty thousand, one hundred thirty-three".