1143410314133 has 4 divisors (see below), whose sum is σ = 1154511385248. Its totient is φ = 1132309243020.

The previous prime is 1143410314103. The next prime is 1143410314139. The reversal of 1143410314133 is 3314130143411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1143410314133 - 2⁶ = 1143410314069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1143410314096 and 1143410314105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1143410314139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5550535403 + ... + 5550535608.

It is an arithmetic number, because the mean of its divisors is an integer number (288627846312).

Almost surely, 2^{1143410314133} is an apocalyptic number.

It is an amenable number.

1143410314133 is a deficient number, since it is larger than the sum of its proper divisors (11101071115).

1143410314133 is a wasteful number, since it uses less digits than its factorization.

1143410314133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11101071114.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1143410314133 its reverse (3314130143411), we get a palindrome (4457540457544).

The spelling of 1143410314133 in words is "one trillion, one hundred forty-three billion, four hundred ten million, three hundred fourteen thousand, one hundred thirty-three".