Base | Representation |
---|---|
bin | 11001111111111010101101… |
… | …000001100010000100111101 |
3 | 112222212010121122220001211210 |
4 | 121333322231001202010331 |
5 | 104441401013141323310 |
6 | 1043104404451035033 |
7 | 33041022034256244 |
oct | 3177725501420475 |
9 | 488763548801753 |
10 | 114343522214205 |
11 | 334848a73a6829 |
12 | 109a865a29ba79 |
13 | 4ba57178c485b |
14 | 203438269195b |
15 | d3450dbac820 |
hex | 67fead06213d |
114343522214205 has 32 divisors (see below), whose sum is σ = 184098496412160. Its totient is φ = 60600727841600.
The previous prime is 114343522214191. The next prime is 114343522214231. The reversal of 114343522214205 is 502412225343411.
It is a de Polignac number, because none of the positive numbers 2k-114343522214205 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10778787 + ... + 18570656.
It is an arithmetic number, because the mean of its divisors is an integer number (5753078012880).
Almost surely, 2114343522214205 is an apocalyptic number.
114343522214205 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
114343522214205 is a deficient number, since it is larger than the sum of its proper divisors (69754974197955).
114343522214205 is a wasteful number, since it uses less digits than its factorization.
114343522214205 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29351081.
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 114343522214205 its reverse (502412225343411), we get a palindrome (616755747557616).
The spelling of 114343522214205 in words is "one hundred fourteen trillion, three hundred forty-three billion, five hundred twenty-two million, two hundred fourteen thousand, two hundred five".
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