11435497213181 has 2 divisors, whose sum is σ = 11435497213182. Its totient is φ = 11435497213180.

The previous prime is 11435497213171. The next prime is 11435497213183. The reversal of 11435497213181 is 18131279453411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8187810259225 + 3247686953956 = 2861435^2 + 1802134^2 .

It is a cyclic number.

It is not a de Polignac number, because 11435497213181 - 2¹⁰ = 11435497212157 is a prime.

It is a super-2 number, since 2×11435497213181² (a number of 27 digits) contains 22 as substring.

Together with 11435497213183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11435497213183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5717748606590 + 5717748606591.

It is an arithmetic number, because the mean of its divisors is an integer number (5717748606591).

Almost surely, 2^{11435497213181} is an apocalyptic number.

It is an amenable number.

11435497213181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11435497213181 is an equidigital number, since it uses as much as digits as its factorization.

11435497213181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 725760, while the sum is 50.

The spelling of 11435497213181 in words is "eleven trillion, four hundred thirty-five billion, four hundred ninety-seven million, two hundred thirteen thousand, one hundred eighty-one".