114401351 has 2 divisors, whose sum is σ = 114401352. Its totient is φ = 114401350.

The previous prime is 114401327. The next prime is 114401363. The reversal of 114401351 is 153104411.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (153104411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114401351 is a prime.

It is a super-2 number, since 2×114401351² = 26175338221250402, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114401051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57200675 + 57200676.

It is an arithmetic number, because the mean of its divisors is an integer number (57200676).

Almost surely, 2^114401351 is an apocalyptic number.

114401351 is a deficient number, since it is larger than the sum of its proper divisors (1).

114401351 is an equidigital number, since it uses as much as digits as its factorization.

114401351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 114401351 is about 10695.8567211795. The cubic root of 114401351 is about 485.4491195292.

Adding to 114401351 its reverse (153104411), we get a palindrome (267505762).

The spelling of 114401351 in words is "one hundred fourteen million, four hundred one thousand, three hundred fifty-one".