1144014253111 has 4 divisors (see below), whose sum is σ = 1165599427752. Its totient is φ = 1122429078472.

The previous prime is 1144014253099. The next prime is 1144014253147. The reversal of 1144014253111 is 1113524104411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1144014253111 - 2¹¹ = 1144014251063 is a prime.

It is a super-2 number, since 2×1144014253111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1144014253111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1144014293111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10792587241 + ... + 10792587346.

It is an arithmetic number, because the mean of its divisors is an integer number (291399856938).

Almost surely, 2^{1144014253111} is an apocalyptic number.

1144014253111 is a deficient number, since it is larger than the sum of its proper divisors (21585174641).

1144014253111 is an equidigital number, since it uses as much as digits as its factorization.

1144014253111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21585174640.

The product of its (nonzero) digits is 1920, while the sum is 28.

Adding to 1144014253111 its reverse (1113524104411), we get a palindrome (2257538357522).

The spelling of 1144014253111 in words is "one trillion, one hundred forty-four billion, fourteen million, two hundred fifty-three thousand, one hundred eleven".