Base | Representation |
---|---|
bin | 110101010001101100… |
… | …0110001111101110011 |
3 | 101221022110020001112102 |
4 | 1222203120301331303 |
5 | 3333303021111034 |
6 | 124320454251015 |
7 | 11160123530204 |
oct | 1524330617563 |
9 | 357273201472 |
10 | 114410332019 |
11 | 44580716905 |
12 | 1a20b956a6b |
13 | aa34139919 |
14 | 5774c2b5ab |
15 | 2e993c297e |
hex | 1aa3631f73 |
114410332019 has 2 divisors, whose sum is σ = 114410332020. Its totient is φ = 114410332018.
The previous prime is 114410332013. The next prime is 114410332021. The reversal of 114410332019 is 910233014411.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114410332019 is a prime.
It is a super-2 number, since 2×1144103320192 (a number of 23 digits) contains 22 as substring.
Together with 114410332021, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 114410331982 and 114410332000.
It is not a weakly prime, because it can be changed into another prime (114410332013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57205166009 + 57205166010.
It is an arithmetic number, because the mean of its divisors is an integer number (57205166010).
Almost surely, 2114410332019 is an apocalyptic number.
114410332019 is a deficient number, since it is larger than the sum of its proper divisors (1).
114410332019 is an equidigital number, since it uses as much as digits as its factorization.
114410332019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 114410332019 in words is "one hundred fourteen billion, four hundred ten million, three hundred thirty-two thousand, nineteen".
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