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114410332019 is a prime number
BaseRepresentation
bin110101010001101100…
…0110001111101110011
3101221022110020001112102
41222203120301331303
53333303021111034
6124320454251015
711160123530204
oct1524330617563
9357273201472
10114410332019
1144580716905
121a20b956a6b
13aa34139919
145774c2b5ab
152e993c297e
hex1aa3631f73

114410332019 has 2 divisors, whose sum is σ = 114410332020. Its totient is φ = 114410332018.

The previous prime is 114410332013. The next prime is 114410332021. The reversal of 114410332019 is 910233014411.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114410332019 is a prime.

It is a super-2 number, since 2×1144103320192 (a number of 23 digits) contains 22 as substring.

Together with 114410332021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 114410331982 and 114410332000.

It is not a weakly prime, because it can be changed into another prime (114410332013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57205166009 + 57205166010.

It is an arithmetic number, because the mean of its divisors is an integer number (57205166010).

Almost surely, 2114410332019 is an apocalyptic number.

114410332019 is a deficient number, since it is larger than the sum of its proper divisors (1).

114410332019 is an equidigital number, since it uses as much as digits as its factorization.

114410332019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 114410332019 in words is "one hundred fourteen billion, four hundred ten million, three hundred thirty-two thousand, nineteen".