114413054130 has 96 divisors (see below), whose sum is σ = 300083097600. Its totient is φ = 30242975616.

The previous prime is 114413054089. The next prime is 114413054131. The reversal of 114413054130 is 31450314411.

114413054130 is a `hidden beast` number, since 11 + 441 + 30 + 54 + 130 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 114413054094 and 114413054103.

It is not an unprimeable number, because it can be changed into a prime (114413054131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15072376 + ... + 15079964.

It is an arithmetic number, because the mean of its divisors is an integer number (3125865600).

Almost surely, 2^114413054130 is an apocalyptic number.

114413054130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 114413054130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (150041548800).

114413054130 is an abundant number, since it is smaller than the sum of its proper divisors (185670043470).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114413054130 is a wasteful number, since it uses less digits than its factorization.

114413054130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9048 (or 9045 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 114413054130 its reverse (31450314411), we get a palindrome (145863368541).

The spelling of 114413054130 in words is "one hundred fourteen billion, four hundred thirteen million, fifty-four thousand, one hundred thirty".