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1144310304403 = 7163472900629
BaseRepresentation
bin10000101001101110001…
…101011000111010010011
311001101122221201110022001
4100221232031120322103
5122222021414220103
62233404445054431
7145450035046330
oct20515615307223
94041587643261
101144310304403
11401332375582
12165937257417
1383ba5b472c6
143d5562c1987
151eb75aa501d
hex10a6e358e93

1144310304403 has 4 divisors (see below), whose sum is σ = 1307783205040. Its totient is φ = 980837403768.

The previous prime is 1144310304373. The next prime is 1144310304461. The reversal of 1144310304403 is 3044030134411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1144310304403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1144310304803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81736450308 + ... + 81736450321.

It is an arithmetic number, because the mean of its divisors is an integer number (326945801260).

Almost surely, 21144310304403 is an apocalyptic number.

1144310304403 is a deficient number, since it is larger than the sum of its proper divisors (163472900637).

1144310304403 is an equidigital number, since it uses as much as digits as its factorization.

1144310304403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163472900636.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1144310304403 its reverse (3044030134411), we get a palindrome (4188340438814).

The spelling of 1144310304403 in words is "one trillion, one hundred forty-four billion, three hundred ten million, three hundred four thousand, four hundred three".

Divisors: 1 7 163472900629 1144310304403