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1144311114431 is a prime number
BaseRepresentation
bin10000101001101110010…
…000011110101010111111
311001101200000020121110002
4100221232100132222333
5122222022121130211
62233404514304515
7145450044662042
oct20515620365277
94041600217402
101144311114431
11401332879121
1216593758813b
1383ba606bc04
143d556452c59
151eb75bb503b
hex10a6e41eabf

1144311114431 has 2 divisors, whose sum is σ = 1144311114432. Its totient is φ = 1144311114430.

The previous prime is 1144311114409. The next prime is 1144311114433. The reversal of 1144311114431 is 1344111134411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1144311114431 - 26 = 1144311114367 is a prime.

It is a super-2 number, since 2×11443111144312 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1144311114433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1144311114394 and 1144311114403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1144311114433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572155557215 + 572155557216.

It is an arithmetic number, because the mean of its divisors is an integer number (572155557216).

Almost surely, 21144311114431 is an apocalyptic number.

1144311114431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1144311114431 is an equidigital number, since it uses as much as digits as its factorization.

1144311114431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 29.

Adding to 1144311114431 its reverse (1344111134411), we get a palindrome (2488422248842).

The spelling of 1144311114431 in words is "one trillion, one hundred forty-four billion, three hundred eleven million, one hundred fourteen thousand, four hundred thirty-one".