11443241323 has 4 divisors (see below), whose sum is σ = 11604413808. Its totient is φ = 11282068840.

The previous prime is 11443241317. The next prime is 11443241419. The reversal of 11443241323 is 32314234411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11443241323 is a prime.

It is a super-3 number, since 3×11443241323³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11443241291 and 11443241300.

It is not an unprimeable number, because it can be changed into a prime (11443241023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80586136 + ... + 80586277.

It is an arithmetic number, because the mean of its divisors is an integer number (2901103452).

Almost surely, 2^11443241323 is an apocalyptic number.

11443241323 is a deficient number, since it is larger than the sum of its proper divisors (161172485).

11443241323 is an equidigital number, since it uses as much as digits as its factorization.

11443241323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161172484.

The product of its digits is 6912, while the sum is 28.

Subtracting from 11443241323 its product of digits (6912), we obtain a palindrome (11443234411).

Adding to 11443241323 its reverse (32314234411), we get a palindrome (43757475734).

The spelling of 11443241323 in words is "eleven billion, four hundred forty-three million, two hundred forty-one thousand, three hundred twenty-three".