Base | Representation |
---|---|
bin | 10101010100001010… |
… | …10011010011110101 |
3 | 1002112111212112211011 |
4 | 22222011103103311 |
5 | 141414010414000 |
6 | 5131304512221 |
7 | 553402505161 |
oct | 125205232365 |
9 | 32474775734 |
10 | 11443451125 |
11 | 4942591227 |
12 | 227447b671 |
13 | 1104a70572 |
14 | 7a7b45ca1 |
15 | 46e9872ba |
hex | 2aa1534f5 |
11443451125 has 16 divisors (see below), whose sum is σ = 14293805760. Its totient is φ = 9146826000.
The previous prime is 11443451093. The next prime is 11443451137. The reversal of 11443451125 is 52115434411.
11443451125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11443451125 - 25 = 11443451093 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 107286 + ... + 185464.
It is an arithmetic number, because the mean of its divisors is an integer number (893362860).
Almost surely, 211443451125 is an apocalyptic number.
It is an amenable number.
11443451125 is a deficient number, since it is larger than the sum of its proper divisors (2850354635).
11443451125 is an equidigital number, since it uses as much as digits as its factorization.
11443451125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79365 (or 79355 counting only the distinct ones).
The product of its digits is 9600, while the sum is 31.
Adding to 11443451125 its reverse (52115434411), we get a palindrome (63558885536).
The spelling of 11443451125 in words is "eleven billion, four hundred forty-three million, four hundred fifty-one thousand, one hundred twenty-five".
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