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11444002133 = 69623164371
BaseRepresentation
bin10101010100001110…
…11001110101010101
31002112112220112122212
422222013121311111
5141414131032013
65131324403205
7553410261464
oct125207316525
932475815585
1011444002133
114942928203
1222746a6505
131104c042c5
147a7c4a9db
1546ea456a8
hex2aa1d9d55

11444002133 has 4 divisors (see below), whose sum is σ = 11444236128. Its totient is φ = 11443768140.

The previous prime is 11444002109. The next prime is 11444002177. The reversal of 11444002133 is 33120044411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11444002133 - 210 = 11444001109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11444002099 and 11444002108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11444002033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12563 + ... + 151808.

It is an arithmetic number, because the mean of its divisors is an integer number (2861059032).

Almost surely, 211444002133 is an apocalyptic number.

It is an amenable number.

11444002133 is a deficient number, since it is larger than the sum of its proper divisors (233995).

11444002133 is an equidigital number, since it uses as much as digits as its factorization.

11444002133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233994.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11444002133 its reverse (33120044411), we get a palindrome (44564046544).

The spelling of 11444002133 in words is "eleven billion, four hundred forty-four million, two thousand, one hundred thirty-three".

Divisors: 1 69623 164371 11444002133