11444211431133 has 8 divisors (see below), whose sum is σ = 16432713849888. Its totient is φ = 7042591649904.

The previous prime is 11444211431099. The next prime is 11444211431167. The reversal of 11444211431133 is 33113411244411.

It is an interprime number because it is at equal distance from previous prime (11444211431099) and next prime (11444211431167).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11444211431133 - 2²¹ = 11444209333981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11444211431094 and 11444211431103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11444211431833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 146720659335 + ... + 146720659412.

It is an arithmetic number, because the mean of its divisors is an integer number (2054089231236).

Almost surely, 2^{11444211431133} is an apocalyptic number.

11444211431133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11444211431133 is a deficient number, since it is larger than the sum of its proper divisors (4988502418755).

11444211431133 is a wasteful number, since it uses less digits than its factorization.

11444211431133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 293441318763.

The product of its digits is 13824, while the sum is 33.

Adding to 11444211431133 its reverse (33113411244411), we get a palindrome (44557622675544).

The spelling of 11444211431133 in words is "eleven trillion, four hundred forty-four billion, two hundred eleven million, four hundred thirty-one thousand, one hundred thirty-three".