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11448715244663 is a prime number
BaseRepresentation
bin1010011010011001110010…
…0110101111010001110111
31111112111010122112212221002
42212212130212233101313
53000033432100312123
640203244524313515
72261066556631604
oct246463446572167
944474118485832
1011448715244663
113714411319694
12134aa076a289b
136507bc5a3c48
142b81995956ab
1514cc19c69528
hexa699c9af477

11448715244663 has 2 divisors, whose sum is σ = 11448715244664. Its totient is φ = 11448715244662.

The previous prime is 11448715244599. The next prime is 11448715244711. The reversal of 11448715244663 is 36644251784411.

It is a strong prime.

It is an emirp because it is prime and its reverse (36644251784411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11448715244663 - 26 = 11448715244599 is a prime.

It is a super-3 number, since 3×114487152446633 (a number of 40 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 11448715244599 and 11448715244608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11448715244363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5724357622331 + 5724357622332.

It is an arithmetic number, because the mean of its divisors is an integer number (5724357622332).

Almost surely, 211448715244663 is an apocalyptic number.

11448715244663 is a deficient number, since it is larger than the sum of its proper divisors (1).

11448715244663 is an equidigital number, since it uses as much as digits as its factorization.

11448715244663 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15482880, while the sum is 56.

The spelling of 11448715244663 in words is "eleven trillion, four hundred forty-eight billion, seven hundred fifteen million, two hundred forty-four thousand, six hundred sixty-three".