Search a number
-
+
11448715244711 is a prime number
BaseRepresentation
bin1010011010011001110010…
…0110101111010010100111
31111112111010122112212222212
42212212130212233102213
53000033432100312321
640203244524314035
72261066556632003
oct246463446572247
944474118485885
1011448715244711
113714411319728
12134aa076a291b
136507bc5a3c84
142b8199595703
1514cc19c6955b
hexa699c9af4a7

11448715244711 has 2 divisors, whose sum is σ = 11448715244712. Its totient is φ = 11448715244710.

The previous prime is 11448715244663. The next prime is 11448715244717. The reversal of 11448715244711 is 11744251784411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11448715244711 - 210 = 11448715243687 is a prime.

It is a super-2 number, since 2×114487152447112 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11448715244711.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11448715244717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5724357622355 + 5724357622356.

It is an arithmetic number, because the mean of its divisors is an integer number (5724357622356).

Almost surely, 211448715244711 is an apocalyptic number.

11448715244711 is a deficient number, since it is larger than the sum of its proper divisors (1).

11448715244711 is an equidigital number, since it uses as much as digits as its factorization.

11448715244711 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1003520, while the sum is 50.

The spelling of 11448715244711 in words is "eleven trillion, four hundred forty-eight billion, seven hundred fifteen million, two hundred forty-four thousand, seven hundred eleven".