114502340133 has 12 divisors (see below), whose sum is σ = 166007113740. Its totient is φ = 76051118976.

The previous prime is 114502340131. The next prime is 114502340137. The reversal of 114502340133 is 331043205411.

It is a happy number.

114502340133 is a `hidden beast` number, since 114 + 502 + 3 + 40 + 1 + 3 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 16005539169 + 98496800964 = 126513^2 + 313842^2 .

It is not a de Polignac number, because 114502340133 - 2¹ = 114502340131 is a prime.

It is a super-2 number, since 2×114502340133² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114502340097 and 114502340106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114502340131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23645316 + ... + 23650157.

It is an arithmetic number, because the mean of its divisors is an integer number (13833926145).

Almost surely, 2^114502340133 is an apocalyptic number.

It is an amenable number.

114502340133 is a deficient number, since it is larger than the sum of its proper divisors (51504773607).

114502340133 is a wasteful number, since it uses less digits than its factorization.

114502340133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47295748 (or 47295745 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 114502340133 its reverse (331043205411), we get a palindrome (445545545544).

The spelling of 114502340133 in words is "one hundred fourteen billion, five hundred two million, three hundred forty thousand, one hundred thirty-three".