Base | Representation |
---|---|
bin | 11010000010010110111110… |
… | …100011011100101000001111 |
3 | 120000110011201210002220121112 |
4 | 122002112332203130220033 |
5 | 110002123140412320444 |
6 | 1043313435120522235 |
7 | 33056112155260256 |
oct | 3202267643345017 |
9 | 500404653086545 |
10 | 114511320041999 |
11 | 33539a83950371 |
12 | 10a1508948037b |
13 | 4bb84a953965a |
14 | 203c53da8379d |
15 | d38a8000c69e |
hex | 6825be8dca0f |
114511320041999 has 2 divisors, whose sum is σ = 114511320042000. Its totient is φ = 114511320041998.
The previous prime is 114511320041959. The next prime is 114511320042001. The reversal of 114511320041999 is 999140023115411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114511320041999 - 224 = 114511303264783 is a prime.
It is a super-2 number, since 2×1145113200419992 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 114511320042001, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114511320041959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57255660020999 + 57255660021000.
It is an arithmetic number, because the mean of its divisors is an integer number (57255660021000).
Almost surely, 2114511320041999 is an apocalyptic number.
114511320041999 is a deficient number, since it is larger than the sum of its proper divisors (1).
114511320041999 is an equidigital number, since it uses as much as digits as its factorization.
114511320041999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 349920, while the sum is 50.
The spelling of 114511320041999 in words is "one hundred fourteen trillion, five hundred eleven billion, three hundred twenty million, forty-one thousand, nine hundred ninety-nine".
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