Base | Representation |
---|---|
bin | 1010011010101110010000… |
… | …1100100111010011111010 |
3 | 1111120000022200101121012211 |
4 | 2212223210030213103322 |
5 | 3000131211044320010 |
6 | 40205554140325334 |
7 | 2261353014551152 |
oct | 246534414472372 |
9 | 44500280347184 |
10 | 11454211323130 |
11 | 37167817547a4 |
12 | 134baa024384a |
13 | 651187143994 |
14 | 2b855b4ab762 |
15 | 14ce3c51208a |
hex | a6ae43274fa |
11454211323130 has 32 divisors (see below), whose sum is σ = 20791908144000. Its totient is φ = 4543102187712.
The previous prime is 11454211323109. The next prime is 11454211323167. The reversal of 11454211323130 is 3132311245411.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 11454211323092 and 11454211323101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9239260 + ... + 10405399.
It is an arithmetic number, because the mean of its divisors is an integer number (649747129500).
Almost surely, 211454211323130 is an apocalyptic number.
11454211323130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11454211323130 is a deficient number, since it is larger than the sum of its proper divisors (9337696820870).
11454211323130 is a wasteful number, since it uses less digits than its factorization.
11454211323130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19645158.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 11454211323130 its reverse (3132311245411), we get a palindrome (14586522568541).
The spelling of 11454211323130 in words is "eleven trillion, four hundred fifty-four billion, two hundred eleven million, three hundred twenty-three thousand, one hundred thirty".
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