114542230114541 has 2 divisors, whose sum is σ = 114542230114542. Its totient is φ = 114542230114540.

The previous prime is 114542230114519. The next prime is 114542230114579. The reversal of 114542230114541 is 145411032245411.

It is an a-pointer prime, because the next prime (114542230114579) can be obtained adding 114542230114541 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114439715522500 + 102514592041 = 10697650^2 + 320179^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114542230114541 is a prime.

It is a super-2 number, since 2×114542230114541² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114542230114495 and 114542230114504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114542230114441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57271115057270 + 57271115057271.

It is an arithmetic number, because the mean of its divisors is an integer number (57271115057271).

Almost surely, 2^{114542230114541} is an apocalyptic number.

It is an amenable number.

114542230114541 is a deficient number, since it is larger than the sum of its proper divisors (1).

114542230114541 is an equidigital number, since it uses as much as digits as its factorization.

114542230114541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76800, while the sum is 38.

Adding to 114542230114541 its reverse (145411032245411), we get a palindrome (259953262359952).

The spelling of 114542230114541 in words is "one hundred fourteen trillion, five hundred forty-two billion, two hundred thirty million, one hundred fourteen thousand, five hundred forty-one".