11455113105 has 12 divisors (see below), whose sum is σ = 19855529460. Its totient is φ = 6109393632.

The previous prime is 11455113083. The next prime is 11455113127. The reversal of 11455113105 is 50131155411.

11455113105 is a `hidden beast` number, since 1 + 1 + 4 + 551 + 1 + 3 + 105 = 666.

11455113105 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11455113083) and next prime (11455113127).

It can be written as a sum of positive squares in 2 ways, for example, as 1589856129 + 9865256976 = 39873^2 + 99324^2 .

It is not a de Polignac number, because 11455113105 - 2³⁰ = 10381371281 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 127278990 + ... + 127279079.

It is an arithmetic number, because the mean of its divisors is an integer number (1654627455).

Almost surely, 2^11455113105 is an apocalyptic number.

11455113105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11455113105 is a deficient number, since it is larger than the sum of its proper divisors (8400416355).

11455113105 is a wasteful number, since it uses less digits than its factorization.

11455113105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254558080 (or 254558077 counting only the distinct ones).

The product of its (nonzero) digits is 1500, while the sum is 27.

Adding to 11455113105 its reverse (50131155411), we get a palindrome (61586268516).

The spelling of 11455113105 in words is "eleven billion, four hundred fifty-five million, one hundred thirteen thousand, one hundred five".