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11455142131231 = 13738343147947
BaseRepresentation
bin1010011010110001101110…
…1011010111011000011111
31111120002201112212112212221
42212230123223113120133
53000140112341144411
640210230351010211
72261415046362331
oct246543353273037
944502645775787
1011455142131231
11371710a109697
1213500bbb09967
136512a4c360c6
142b8608d67451
1514ce940c7071
hexa6b1bad761f

11455142131231 has 4 divisors (see below), whose sum is σ = 11463485280552. Its totient is φ = 11446798981912.

The previous prime is 11455142131163. The next prime is 11455142131247. The reversal of 11455142131231 is 13213124155411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11455142131231 - 213 = 11455142123039 is a prime.

It is a super-2 number, since 2×114551421312312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11455142141231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4171572601 + ... + 4171575346.

It is an arithmetic number, because the mean of its divisors is an integer number (2865871320138).

Almost surely, 211455142131231 is an apocalyptic number.

11455142131231 is a deficient number, since it is larger than the sum of its proper divisors (8343149321).

11455142131231 is an equidigital number, since it uses as much as digits as its factorization.

11455142131231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8343149320.

The product of its digits is 14400, while the sum is 34.

Adding to 11455142131231 its reverse (13213124155411), we get a palindrome (24668266286642).

The spelling of 11455142131231 in words is "eleven trillion, four hundred fifty-five billion, one hundred forty-two million, one hundred thirty-one thousand, two hundred thirty-one".

Divisors: 1 1373 8343147947 11455142131231