Base | Representation |
---|---|
bin | 110101010101111100… |
… | …1011111100010100111 |
3 | 101221200101220200201111 |
4 | 1222223321133202213 |
5 | 3334101100000111 |
6 | 124342555005451 |
7 | 11163506332312 |
oct | 1525371374247 |
9 | 357611820644 |
10 | 114553125031 |
11 | 44644286364 |
12 | 1a24b739887 |
13 | aa578b4327 |
14 | 5789b9b979 |
15 | 2ea6bcba21 |
hex | 1aabe5f8a7 |
114553125031 has 2 divisors, whose sum is σ = 114553125032. Its totient is φ = 114553125030.
The previous prime is 114553124999. The next prime is 114553125061. The reversal of 114553125031 is 130521355411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114553125031 - 25 = 114553124999 is a prime.
It is a super-2 number, since 2×1145531250312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114553124984 and 114553125002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114553125061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57276562515 + 57276562516.
It is an arithmetic number, because the mean of its divisors is an integer number (57276562516).
Almost surely, 2114553125031 is an apocalyptic number.
114553125031 is a deficient number, since it is larger than the sum of its proper divisors (1).
114553125031 is an equidigital number, since it uses as much as digits as its factorization.
114553125031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 114553125031 in words is "one hundred fourteen billion, five hundred fifty-three million, one hundred twenty-five thousand, thirty-one".
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