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11483249669 is a prime number
BaseRepresentation
bin10101011000111010…
…00111110000000101
31002122021202112011022
422230131013300011
5142004202442134
65135245520525
7554365004003
oct125435076005
932567675138
1011483249669
114962aa4491
122285873145
1311100964b8
147ad145a73
154731e952e
hex2ac747c05

11483249669 has 2 divisors, whose sum is σ = 11483249670. Its totient is φ = 11483249668.

The previous prime is 11483249651. The next prime is 11483249671. The reversal of 11483249669 is 96694238411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10292102500 + 1191147169 = 101450^2 + 34513^2 .

It is a cyclic number.

It is not a de Polignac number, because 11483249669 - 212 = 11483245573 is a prime.

It is a super-2 number, since 2×114832496692 (a number of 21 digits) contains 22 as substring.

Together with 11483249671, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11483249669.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11483246669) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5741624834 + 5741624835.

It is an arithmetic number, because the mean of its divisors is an integer number (5741624835).

Almost surely, 211483249669 is an apocalyptic number.

It is an amenable number.

11483249669 is a deficient number, since it is larger than the sum of its proper divisors (1).

11483249669 is an equidigital number, since it uses as much as digits as its factorization.

11483249669 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2239488, while the sum is 53.

The spelling of 11483249669 in words is "eleven billion, four hundred eighty-three million, two hundred forty-nine thousand, six hundred sixty-nine".