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114850142117 is a prime number
BaseRepresentation
bin110101011110110011…
…0100001011110100101
3101222110002210201120022
41222331212201132211
53340203114021432
6124432245044525
711204044046324
oct1527546413645
9358402721508
10114850142117
1144786a02727
121a3130b6745
13aaa42a9499
1457b73d60bb
152ec2cebb12
hex1abd9a17a5

114850142117 has 2 divisors, whose sum is σ = 114850142118. Its totient is φ = 114850142116.

The previous prime is 114850142101. The next prime is 114850142119. The reversal of 114850142117 is 711241058411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79523436001 + 35326706116 = 281999^2 + 187954^2 .

It is a cyclic number.

It is not a de Polignac number, because 114850142117 - 24 = 114850142101 is a prime.

Together with 114850142119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114850142119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57425071058 + 57425071059.

It is an arithmetic number, because the mean of its divisors is an integer number (57425071059).

Almost surely, 2114850142117 is an apocalyptic number.

It is an amenable number.

114850142117 is a deficient number, since it is larger than the sum of its proper divisors (1).

114850142117 is an equidigital number, since it uses as much as digits as its factorization.

114850142117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8960, while the sum is 35.

The spelling of 114850142117 in words is "one hundred fourteen billion, eight hundred fifty million, one hundred forty-two thousand, one hundred seventeen".