Base | Representation |
---|---|
bin | 10101011001011010… |
… | …00001001100101011 |
3 | 1002122120121020211202 |
4 | 22230231001030223 |
5 | 142011234322011 |
6 | 5135515114415 |
7 | 554445302021 |
oct | 125455011453 |
9 | 32576536752 |
10 | 11487417131 |
11 | 4965390573 |
12 | 2287142a0b |
13 | 1110bc5358 |
14 | 7ad90c711 |
15 | 47376e23b |
hex | 2acb4132b |
11487417131 has 2 divisors, whose sum is σ = 11487417132. Its totient is φ = 11487417130.
The previous prime is 11487417101. The next prime is 11487417169. The reversal of 11487417131 is 13171478411.
It is a happy number.
It is an a-pointer prime, because the next prime (11487417169) can be obtained adding 11487417131 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11487417131 - 214 = 11487400747 is a prime.
It is a super-2 number, since 2×114874171312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11487417101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5743708565 + 5743708566.
It is an arithmetic number, because the mean of its divisors is an integer number (5743708566).
Almost surely, 211487417131 is an apocalyptic number.
11487417131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11487417131 is an equidigital number, since it uses as much as digits as its factorization.
11487417131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18816, while the sum is 38.
The spelling of 11487417131 in words is "eleven billion, four hundred eighty-seven million, four hundred seventeen thousand, one hundred thirty-one".
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