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11490121 is a prime number
BaseRepresentation
bin101011110101…
…001101001001
3210121202111001
4223311031021
510420140441
61050135001
7166443616
oct53651511
923552431
1011490121
116538775
123a21461
1324c3bb6
14175150d
15101e731
hexaf5349

11490121 has 2 divisors, whose sum is σ = 11490122. Its totient is φ = 11490120.

The previous prime is 11490107. The next prime is 11490131. The reversal of 11490121 is 12109411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10791225 + 698896 = 3285^2 + 836^2 .

It is an emirp because it is prime and its reverse (12109411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11490121 - 27 = 11489993 is a prime.

It is not a weakly prime, because it can be changed into another prime (11490131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5745060 + 5745061.

It is an arithmetic number, because the mean of its divisors is an integer number (5745061).

Almost surely, 211490121 is an apocalyptic number.

It is an amenable number.

11490121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11490121 is an equidigital number, since it uses as much as digits as its factorization.

11490121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

The square root of 11490121 is about 3389.7080995272. The cubic root of 11490121 is about 225.6532194352.

Adding to 11490121 its reverse (12109411), we get a palindrome (23599532).

It can be divided in two parts, 11490 and 121, that added together give a palindrome (11611).

The spelling of 11490121 in words is "eleven million, four hundred ninety thousand, one hundred twenty-one".