Base | Representation |
---|---|
bin | 100010001111100… |
… | …1000110111111101 |
3 | 2222002001221012121 |
4 | 1010133020313331 |
5 | 4323121413001 |
6 | 310003202541 |
7 | 40321311406 |
oct | 10437106775 |
9 | 2862057177 |
10 | 1149013501 |
11 | 53a651939 |
12 | 280976451 |
13 | 15408205c |
14 | ac85a9ad |
15 | 6ad186a1 |
hex | 447c8dfd |
1149013501 has 2 divisors, whose sum is σ = 1149013502. Its totient is φ = 1149013500.
The previous prime is 1149013499. The next prime is 1149013517. The reversal of 1149013501 is 1053109411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1134005625 + 15007876 = 33675^2 + 3874^2 .
It is a cyclic number.
It is not a de Polignac number, because 1149013501 - 21 = 1149013499 is a prime.
Together with 1149013499, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1149013301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574506750 + 574506751.
It is an arithmetic number, because the mean of its divisors is an integer number (574506751).
Almost surely, 21149013501 is an apocalyptic number.
It is an amenable number.
1149013501 is a deficient number, since it is larger than the sum of its proper divisors (1).
1149013501 is an equidigital number, since it uses as much as digits as its factorization.
1149013501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
The square root of 1149013501 is about 33897.1016607615. The cubic root of 1149013501 is about 1047.3898892960.
The spelling of 1149013501 in words is "one billion, one hundred forty-nine million, thirteen thousand, five hundred one".
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