1149025399 has 4 divisors (see below), whose sum is σ = 1209500440. Its totient is φ = 1088550360.

The previous prime is 1149025391. The next prime is 1149025433. The reversal of 1149025399 is 9935209411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 9935209411 = 17 ⋅584424083.

It is a cyclic number.

It is not a de Polignac number, because 1149025399 - 2³ = 1149025391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1149025391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30237492 + ... + 30237529.

It is an arithmetic number, because the mean of its divisors is an integer number (302375110).

Almost surely, 2^1149025399 is an apocalyptic number.

1149025399 is a gapful number since it is divisible by the number (19) formed by its first and last digit.

1149025399 is a deficient number, since it is larger than the sum of its proper divisors (60475041).

1149025399 is an equidigital number, since it uses as much as digits as its factorization.

1149025399 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60475040.

The product of its (nonzero) digits is 87480, while the sum is 43.

The square root of 1149025399 is about 33897.2771620377. The cubic root of 1149025399 is about 1047.3935045137.

The spelling of 1149025399 in words is "one billion, one hundred forty-nine million, twenty-five thousand, three hundred ninety-nine".