1149512503 has 2 divisors, whose sum is σ = 1149512504. Its totient is φ = 1149512502.

The previous prime is 1149512491. The next prime is 1149512509. The reversal of 1149512503 is 3052159411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1149512503 - 2⁵ = 1149512471 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1149512509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574756251 + 574756252.

It is an arithmetic number, because the mean of its divisors is an integer number (574756252).

Almost surely, 2^1149512503 is an apocalyptic number.

1149512503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1149512503 is an equidigital number, since it uses as much as digits as its factorization.

1149512503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 31.

The square root of 1149512503 is about 33904.4614025942. The cubic root of 1149512503 is about 1047.5414900698.

The spelling of 1149512503 in words is "one billion, one hundred forty-nine million, five hundred twelve thousand, five hundred three".