Base | Representation |
---|---|
bin | 1010011101001101111101… |
… | …1000101011110100100101 |
3 | 1111201002222021212221201211 |
4 | 2213103133120223310211 |
5 | 3001332010022233323 |
6 | 40241404042551421 |
7 | 2264431236614632 |
oct | 247233730536445 |
9 | 44632867787654 |
10 | 11497080274213 |
11 | 37329800a5196 |
12 | 1358264b08571 |
13 | 6552296b5721 |
14 | 2ba666acb189 |
15 | 14e0ead0370d |
hex | a74df62bd25 |
11497080274213 has 2 divisors, whose sum is σ = 11497080274214. Its totient is φ = 11497080274212.
The previous prime is 11497080274157. The next prime is 11497080274217. The reversal of 11497080274213 is 31247208079411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11363593806049 + 133486468164 = 3370993^2 + 365358^2 .
It is a cyclic number.
It is not a de Polignac number, because 11497080274213 - 221 = 11497078177061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11497080274217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5748540137106 + 5748540137107.
It is an arithmetic number, because the mean of its divisors is an integer number (5748540137107).
Almost surely, 211497080274213 is an apocalyptic number.
It is an amenable number.
11497080274213 is a deficient number, since it is larger than the sum of its proper divisors (1).
11497080274213 is an equidigital number, since it uses as much as digits as its factorization.
11497080274213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 677376, while the sum is 49.
The spelling of 11497080274213 in words is "eleven trillion, four hundred ninety-seven billion, eighty million, two hundred seventy-four thousand, two hundred thirteen".
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