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11497080274217 is a prime number
BaseRepresentation
bin1010011101001101111101…
…1000101011110100101001
31111201002222021212221201222
42213103133120223310221
53001332010022233332
640241404042551425
72264431236614636
oct247233730536451
944632867787658
1011497080274217
1137329800a519a
121358264b08575
136552296b5725
142ba666acb18d
1514e0ead03712
hexa74df62bd29

11497080274217 has 2 divisors, whose sum is σ = 11497080274218. Its totient is φ = 11497080274216.

The previous prime is 11497080274213. The next prime is 11497080274219. The reversal of 11497080274217 is 71247208079411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7780439950336 + 3716640323881 = 2789344^2 + 1927859^2 .

It is a cyclic number.

It is not a de Polignac number, because 11497080274217 - 22 = 11497080274213 is a prime.

Together with 11497080274219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11497080274213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5748540137108 + 5748540137109.

It is an arithmetic number, because the mean of its divisors is an integer number (5748540137109).

Almost surely, 211497080274217 is an apocalyptic number.

It is an amenable number.

11497080274217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11497080274217 is an equidigital number, since it uses as much as digits as its factorization.

11497080274217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1580544, while the sum is 53.

The spelling of 11497080274217 in words is "eleven trillion, four hundred ninety-seven billion, eighty million, two hundred seventy-four thousand, two hundred seventeen".